[英]List comprehension
I want to fill a list, according to another list with scores.我想填写一个列表,根据另一个带有分数的列表。 I have found a way but was wondering whether it could be done with list comprehension as well.
我找到了一种方法,但想知道是否也可以通过列表理解来完成。
I have a list mood_options
with strings and a list with weekly_scores
with integers.我有一个带有字符串的列表
mood_options
和一个带有整数的weekly_scores
列表。 I use the integers from the weekly_scores
as an index to pick from the mood_options
list.我使用来自
weekly_scores
的整数作为从mood_options
列表中选择的索引。 Then, these elements picked from mood_options
are put in a list called weekly_moods
.然后,从
mood_options
中挑选的这些元素被放入一个名为weekly_moods
的列表中。
This I how I achieved it with a for loop:这是我如何通过 for 循环实现的:
mood_options = ["awful", "bad", "meh", "good", "amazing"]
weekly_scores = [2, 4, 1, 3, 4, 2, 4]
weekly_moods = []
for score in weekly_scores:
weekly_moods.append(mood_options[score-1])
As I said, it works, but I have the feeling it can be more concise using list comprehension, however, I cannot figure out how.正如我所说,它有效,但我觉得使用列表理解可以更简洁,但是,我不知道如何。
Use:用:
weekly_moods = [mood_options[score-1] for score in weekly_scores]
Full Code完整代码
mood_options = ["awful", "bad", "meh", "good", "amazing"]
weekly_scores = [2, 4, 1, 3, 4, 2, 4]
weekly_moods = [mood_options[score - 1] for score in weekly_scores]
print(weekly_moods)
Output输出
['bad', 'good', 'awful', 'meh', 'good', 'bad', 'good']
References参考
It can be written with a list comprehension:它可以用列表理解来编写:
[mood_options[i-1] for i in weekly_scores]
This takes an i from weekly_scores
and uses it to take the correct item out mood_options
这需要从我
weekly_scores
并用它来拿出正确的项目mood_options
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