python3中的异常处理

Question

I was doing one hackerrank challenge via my company website. The question is a simple ValueError raise exception based on the condition - Given two integers a and b - if a > 150 or b < 100 then raise exception. Second condition is if sum of the two integers is greater than 400, then also raise the ValueError exception. If no condition satisfies then print "All values in range". I have written below code and it passed 7 out of 9 test case. Now I am not able to figure where could be my code is failing for those two test cases. It outputs - All values in range - message in the failed test cases. Can someone point what more I can add to the code to pass the remaining two test cases.

def handle_excl():
    a = int(input())
    b = int(input())
    sums = a + b
    
    
    if (a > 150) or (b < 100):
        raise ValueError('Input integers value out of range.')
    elif sums > 400:
        raise ValueError('Their sum is out of range')
    else:
        print('All in range.')

Above is the main code and please help how can I resolve the two failed test cases?

Answer 1

This is in response to a comment I made about the fact that elif and else conditions are unnecessary in this case:

def checkvals(a, b):
  if (a > 150) or (b < 100):
    raise ValueError('Input integers value out of range')
  if a + b > 400:
    raise ValueError('Sum out of range')
  print('All in range')

Answer 2

Your code is correct, you just have to remove the fullstop(.) sign in this line-> print("All in range.")

def handle_excl():
    a = int(input())
    b = int(input())
    sums = a + b

    if (a > 150) or (b < 100):
        raise ValueError('Input integers value out of range.')
    elif sums > 400:
        raise ValueError('Their sum is out of range')
    else:
        print('All in range')