[英]how to resolve overload errors in reactjs
import React from 'react'
import { Link } from 'react-scroll'
import "./Protocol.css"
import { ANALYTICS, TRADE, USERS, TRADERS, VOTES, ZEROES } from "../../Constants"
const Protocol = () => {
return (
<div className="Protocol_container">
<div className="Protocol_heading">
{ANALYTICS}
</div>
<div className="Protocol_content">
<Link>
<p>{ZEROES}</p>{TRADE}
</Link>
<Link >
<p>{ZEROES}</p>{USERS}
</Link>
<Link >
<p>{ZEROES}</p>{TRADERS}
</Link>
<Link>
<p>{ZEROES}</p>{VOTES}
</Link>
</div>
</div>
)
}
export default Protocol
getting err as变得错误
No overload matches this call.没有重载匹配这个调用。 Overload 1 of 2, '(props: LinkProps | Readonly): Link', gave the following error.
重载 1 of 2, '(props: LinkProps | Readonly): Link',出现以下错误。 Property 'to' is missing in type '{ children: (string | Element)[];
类型 '{children: (string | Element)[]; 中缺少属性 'to' }' but required in type 'Readonly'.
}' 但在'只读'类型中是必需的。 Overload 2 of 2, '(props: LinkProps, context: any): Link', gave the following error.
重载 2 of 2, '(props: LinkProps, context: any): Link',出现以下错误。 Property 'to' is missing in type '{ children: (string | Element)[];
类型 '{children: (string | Element)[]; 中缺少属性 'to' }' but required in type 'Readonly'.
}' 但在'只读'类型中是必需的。
链接需要道具到=“去哪里”,如果你不想去任何地方就使用to=“#”
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