将零移到字符串的末尾

Question

I was just doing some leetcode but this blew my mind.

class Solution:
  def moveZeroes(self, nums: List[int]) -> None:
    nums = [0, 1, 0, 3 ,12]
    k = 0
    i=0
    while i < len(nums):
        print(i)
        if nums[i] == 0:
            print('inside if=',i)
            print('before',nums)
            k += 1
            print('removed',nums[i])
            nums.remove(i)
            print('after',nums)
        else:
            i += 1
            print('no change',nums)
    print('final',nums)
    for j in range (k):
        nums.append(0)
    print(nums)

and the output is:

0
inside if= 0
before [0, 1, 0, 3, 12]
element to be removed 0
after [1, 0, 3, 12]
0
no change [1, 0, 3, 12]
->1
->inside if= 1
->before [1, 0, 3, 12]
->element to be removed 0
->after [0, 3, 12]
1
no change [0, 3, 12]
2
no change [0, 3, 12]
final [0, 3, 12]
[0, 3, 12, 0, 0]

How can it remove element 1 if it can read that it has to remove 0?

Answer 1

So I got to know my dumb mistake. Actually remove() is used to remove the element that is mentioned. Like if I type remove(6) from a list a = [1,2,3,4,5,6] . it removes element 6, not the element that is at 6th position. so use pop() to do so.