这是将 x 打印 n 次的正确代码吗？

Question

Is this a right way to write a function that prints x for n times? My code:

def funz(x,n):
    f = (x+"\n")*(n-1) + x
    print(f)

Answer 1

You can use sep argument of print :

def funz(x, n):
    print(*[x]*n, sep='\n')

funz('a', 3)

# Output:
a
a
a

Step by step:

>>> print([x])
['a']

>>> print([x]*n)
['a', 'a', 'a']

>>> print(*[x]*n)
a a a

>>> print(*[x]*n, sep='\n')
a
a
a

Answer 2

for loops are useful for tasks like this. In this case you can do this:

n = int(input())
def funz(x, n):
   for _ in range(n):
      print(x)
funz('x',n)