在 shell 脚本中执行 curl 时找不到命令

Question

I am executing the below curl command in shell script. But I am getting command not found error. So wanted to check if I am making any mistake while executing it.

return = $(curl -s --location --request GET --url 'https://testurl.mywebsite.com/api/accts?Id=trst_id&var=test_var' --header 'type: app/test')

echo "data is: ${return}"

I am getting the error:

return: command not found

Kindly let me know if there is a problem with the way I am trying to execute the curl command.

Thank you.

Answer 1

Like dan pointed out in comments, the extra whotespaces between the variable and command caused the issue. After removing extra whitespaces it worked.

return=$(curl -s --location --request GET --url 'https://testurl.mywebsite.com/api/accts?Id=trst_id&var=test_var' --header 'type: app/test') echo "data is: ${return}"