Pandas 和 Numpy 连续非 Nan 值

Question

I'm trying to use np.where to count consecutive non-NaN values longer than a certain length as shown below:

eg If there are more than 3 consecutive non-NaN values then return True.

Would appreciate any help!

value	consecutive
nan	False
nan	False
1	False
1	False
nan	False
4	True
2	True
3	True
nan	False
nan	False
1	True
3	True
3	True
5	True

Answer 1

The idea is to create groups by testing missing values and mapping using Series.map with Series.value_counts to have only rows with non NaNs filtered by inverted mask ~m :

#convert values to numeric
df['value'] = df['value'].astype(float)

m = df['value'].isna()
s = m.cumsum()

N = 3
df['new'] = s.map(s[~m].value_counts()).ge(N) & ~m
print (df)
    value  consecutive    new
0     NaN        False  False
1     NaN        False  False
2     1.0        False  False
3     1.0        False  False
4     NaN        False  False
5     4.0         True   True
6     2.0         True   True
7     3.0         True   True
8     NaN        False  False
9     NaN        False  False
10    1.0         True   True
11    3.0         True   True
12    3.0         True   True
13    5.0         True   True