[英]How to distinguish between a tuple and a list in Python's structural pattern matching?
I want to use Python's structural pattern matching to distinguish between a tuple (eg representing a point) and a list of tuples.我想使用 Python 的结构模式匹配来区分元组(例如表示一个点)和元组列表。
The straightforward approach does not work though:直截了当的方法不起作用:
def fn(p):
match p:
case (x, y):
print(f"single point: ({x}, {y})")
case [*points]:
print("list of points:")
for x, y in points:
print(f"({x}, {y})")
fn((1, 1))
fn([(1, 1), (2, 2)])
which outputs:输出:
single point: (1, 1)
single point: ((1, 1), (2, 2))
whereas I want it to output:而我想要它 output:
single point: (1, 1)
list of points:
(1, 1)
(2, 2)
Switching the order of the case statements also does not help here.切换 case 语句的顺序在这里也无济于事。
What is a good way to solve this with pattern matching?用模式匹配解决这个问题的好方法是什么?
Use tuple(foo)
for matching a tuple and list(foo)
for matching a list使用
tuple(foo)
匹配元组,使用list(foo)
匹配列表
def fn(p):
match p:
case tuple(contents):
print(f"tuple: {contents}")
case list(contents):
print(f"list: {contents}")
fn((1, 1)) # tuple: (1, 1)
fn([(1, 1), (2, 2)]) # list: [(1, 1), (2, 2)]
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