[英]how to Receive JSON data sent by ajax in PHP
I have the data that want sent to backend, its look like我有想要发送到后端的数据,它看起来像
function lihat(){
let id = "12345678";
let profile = [{name:"dave", department : "Engginering"},
{name:"Tedd", department : "Engginering"}]
$.ajax({
type:'POST',
url:'pages/dashboard/dashboard_be.php'
data:{
cekload : true,
keys : id,
dataList : profile
},
success:function(data){
console.log(data);
}
})
the question, how can I receive all of datas sent by ajax in php script this what I've tried问题,我怎样才能在 php 脚本中接收 ajax 发送的所有数据,这是我试过的
$id = $_POST['keys'];
$cekload = $_POST['cekload'];
$data = json_decode($_POST['dataList'];);
//I wanna parsing the dataList object and then loop it, how to make it ?
thanks, before谢谢,之前
If you're trying to send/receive javascript objects, you need to convert the object to a string before sending and decode it back in php (into an array maybe) before reading.如果您尝试发送/接收 javascript 对象,则需要先将 object 转换为字符串,然后再将其发送并解码回 php(可能是数组),然后再读取。
<script>
let id = "12345678";
let profile = [{name:"dave", department : "Engginering"},
{name:"Tedd", department : "Engginering"}]
$.ajax({
type:'POST',
url:'pages/dashboard/dashboard_be.php',
data:{
cekload : true,
keys : id,
dataList : JSON.stringify(profile)
},
success:function(data){
console.log(data);
}
});
</script>
PHP code: PHP 代码:
<?php
$id = $_POST['keys'];
$cekload = $_POST['cekload'];
$data = json_decode($_POST['dataList'], true);
echo $id;
echo $cekload;
print_r($data);
?>
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