我需要检查 Array1 中的 CHAR 是否包含我的 Array2 中的一些 CHAR，但我不能将 Contains 用于 CHAR... 如何解决？

Question

I need to convert one phone number (badly written) to correct format. Example: + 420 741-854()642. to +420741854642 enter image description here

Answer 1

I think I'd just Regex replace all non digits with nothing;

var messy = "+ 420 741-854()642";
var clean = Regex.Replace(messy, "[^+0-9]", "");

For the regex pattern [^+0-9] this means "a single character that is from, the set of: (all characters except) + or 0 to 9 so in practice this pattern matches the space , hyphen - , parentheses () etc.. And any matched character (ie a bad character) is replaced with nothing

Answer 2

This is a job for RegEx (Regular Expressions):) you could have something like this: /+?\d+/gm which will return three matches from +420741-854()642 as ['+420741', '854', '642'] which can of course then be concatenated. You could always as well replace the '+' with '00' beforehand and just concatenate matches from /\d+/gm. This just matches all digits in the string.

https://regex101.com/ is a great resource for learning RegEx.

Answer 3

Technically, you can filter out digits ( c >= '0' && c <= '9' ) with a help of Linq :

using System.Linq;

...

string source = "+ 420 741-854()642.";

string result = "+" + string.Concat(source.Where(c => c >= '0' && c <= '9'));

Answer 4

If you want to do it in the style you showed in the image then you can fix it by doing this:

        string number = "+ 420 741-854()642.";
        char[] povolene = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', '+' };

        for(int i = 0; i < number.Length; i++) {
            if (povolene.Contains(number[i])) {

                .
                .
                .
            }
        }