如何删除除master之外的所有本地分支并在一个没有别名的命令中开发？

Question

When working on projects with Git Flow or similar workflow where more than one stable branch exists I create a lot of feature branches ( feature/do-something-1 , hotfix/fix-bug-1 , etc.).

Sometimes I need to clear the list of local branches because it is literally impossible to manage them with dozens of rudimentary branches. I usually delete them one at a time by copying and pasting the branch names into the git branch -d command. But it takes so long that it's easier to delete the entire repository and clone again.

I want to delete all of them except master and develop in one command (without writing additional shell script/aliases), but all solutions I've found on the internet only allow you to delete everything except one branch ( master , for example). This is not an appropriate solution. Has anyone faced a similar problem?

Answer 1

 git branch | grep -v " master$" | grep -v " develop$" | xargs git branch -D

Answer 2

Here is a simpler variant of same answer:

git branch -D $(git branch | grep -v -e "master$" -e "develop$")