[英]First non-null value from a list of dicts using Ramda
Let's suppose that I want to get the first value of key that is not null inside this list of objects:假设我想在这个对象列表中获取不是 null 的键的第一个值:
const arr = [
{
"key": null,
"anotherkey": 0
},
{
"another": "ignore"
},
{
"bool": True,
"key": "this!"
}
]
Is there some one-liner using Ramda to do this?是否有一些单线使用 Ramda 来做到这一点? I made it using a for loop.
我使用 for 循环实现了它。
You can use Array.find
to find the first item in the array whose key
property is truthy , then get the key
property.您可以使用
Array.find
查找数组中key
属性为真值的第一项,然后获取key
属性。
const arr = [{ "key": null, "anotherkey": 0 }, { "another": "ignore" }, { "bool": true, "key": "this." } ] const res = arr.find(e => e.key);key. console.log(res)
You asked for the first non-null key but answers so far rely on truthyness.您要求第一个非空键,但到目前为止的答案依赖于真实性。 In JavaScript a non-null value is not necessarily truthy.
在 JavaScript 中,非空值不一定是真的。 Things like
0
, ''
or false
are all non-null values but they are not truthy.诸如
0
、 ''
或false
之类的东西都是非空值,但它们不是真实的。
In my experience it is better to be explicit otherwise you may get unexpected results:根据我的经验,最好是明确的,否则您可能会得到意想不到的结果:
var data = [{key:null, val:1}, {key:0, val:2}, {key:1, val:3}];
find(prop('key'))(data);
//=> {key:1, val:3}
find(propSatisfies(complement(isNil), 'key'))(data);
//=> {key:0, val:2}
With Ramda:与拉姆达:
R.find(R.prop("key"))(arr);
prop
function will return the value of key
for each element. prop
function 将返回每个元素的key
。 find
will return the first truthy
element from those. find
将从这些元素中返回第一个truthy
元素。
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