mongodb - 如果数组中的一组值在另一个给定数组中，则匹配[带有聚合]

Question

I'm looking for a solution since 3 hours and I don't get it yet.

I have the following collection:

{text: 'random text 1', indexes:[1,2] },
{text: 'random text 2', indexes:[1,3] },
{text: 'random text 3', indexes:[2,4] },

and I would like to have only the documents that have all the index values in a given array like for example [1,2,4]

using the example above, I would like to have the following output:

{text: 'random text 1', indexes:[1,2] },
{text: 'random text 3', indexes:[2,4] },

[1,2] is in [1,2,4] -> OK

[1,3] is not in [1,2,4] because of 3 -> Not OK

[1,4] is in [1,2,4] -> OK

Any idea? thanks for your answer: :)

Answer 1

You can use one of this this $match stage:

• Using $setIsSubset into $expr :

{
  "$match": {
    "$expr": {
      "$setIsSubset": ["$indexes",[1,2,4]]
    }
  }
}

Example here

• Using $elemMatch and double negation ( $not and $nin ):

{
  "$match": {
    "indexes": {
      "$not": {
        "$elemMatch": {
          "$nin": [1,2,4]
        }
      }
    }
  }
}

Example here