从 bash 中的文件中获取特定文本

Question

i have problem to show specific text. Example i will get only version number from text in file version.txt this: Version = "0.11.0"

can someone help me?

thanks

Answer 1

You want just the numbers?

Perhaps

awk -F\" '/Version/ {print $2}' version.txt

Answer 2

You can simply use cut :

cat version.txt | cut -d '=' -f2 | xargs

Or awk as others suggested:

cat version.txt | awk '{print $3}'

Both output: 0.11.0

The logic is based on the file format being consistent rather than focusing on the number extraction.
cut : prints the value after = | xargs : trims spaces
awk : prints the value on third place

These allow for example both xxx and xxx-RELEASE