如何在for循环中添加编号？

Question

I have a problem printing the line with the number. How to add numbering before of line? I made a comment on which part.

f = open('filename', "r")
lines = f.readlines()
for line in lines:
    synonyms = []
    print(line) # I want my interface to be, 1. word 2. word, and so on
    answer = input("Answer: ").lower()
    for syn in wordnet.synsets(line.strip()):
        for l in syn.lemmas():
            synonyms.append(l.name())

My code is just printing

word1

Answer:

word2

Answer:

My ideal code is:

1.word1

Answer:

2.word2

Answer:

Answer 1

replace your loop:

for i, line in enumerate(lines):
    print(str(i) + '. ' + str(line))

"i" will be the number waited...

you could use string interpolation if you are at min python3.6

   print(f'{i}. {line}')

Answer 2

Instead of traversing through every line in the lines list, just go through the indexes of every element, and then print the index+1 , as obviously list indexes start from 0, but we want our numbering to start from 1. So, instead of printing only the line, we'll print line_no: line

f = open('filename', "r")
lines = f.readlines()
for line_no in range(len(lines)):
    synonyms = []
    print(f"{line_no+1}: {lines[line_no]}") # I want my interface to be, 1. word 2. word, and so on
    answer = input("Answer: ").lower()
    for syn in wordnet.synsets(line.strip()):
        for l in syn.lemmas():
            synonyms.append(l.name())

Hope my answer helped:D

Answer 3

Try this:

f = open('filename', "r")
lines = f.readlines()
for line_no,line in enumerate(lines):
    synonyms = []
    print(str(line_no+1)+'.'+line) # I want my interface to be, 1. word 2. word, and so on
    answer = input("Answer: ").lower()
    for syn in wordnet.synsets(line.strip()):
        for l in syn.lemmas():
            synonyms.append(l.name())

Answer 4

Add a variable called count and increment it with each iteration of the for loop. Code:

count = 1
f = open('filename', "r")
lines = f.readlines()
for line in lines:
    synonyms = []
    print(str(count) + ". " + line) # I want my interface to be, 1. word 2. word, and so on
    count += 1
    answer = input("Answer: ").lower()
    for syn in wordnet.synsets(line.strip()):
        for l in syn.lemmas():
            synonyms.append(l.name())