将嵌套列表中的项目复制到多个列表

Question

I have a function that has an empty list which gets filled up as a nested list by user input.

def main():
    inputs = []
    inputs_n = int(input("Insert the number of inputs: "))
    print("Input format: n,n,n")
    for num in range(2**inputs_n):
        input_value = input(f"Insert [{num + 1}] row with inputs: ")
        inputs.append(list(int(input_row) for input_row in input_value.split(",")))

this results in the list inputs for example like so: inputs = [[1,0,1],[1,1,1]] . Now I extended the above function by adding 3 empty lists, these lists should be filled up by the respective index number.

 row_1 = []
 row_2 = []
 row_3 = []
 for lists in inputs:
     for index in lists:
         row_1.append(inputs[index - 1][0])
         row_2.append(inputs[index - 1][1])
         row_3.append(inputs[index - 1][2])
 print(row_1, row_2, row_3)

The expected result from the print ( following the example from above ) should be like so, row_1: [1,1] row_2: [0,1] row_3: [1,1] . But the result that I get ( still following the example list from above ) is like so:

[1, 1, 1, 1, 1, 1] [0, 1, 0, 0, 0, 0] [1, 1, 1, 1, 1, 1]

Hope the question is clear enough now, If you need any further explanation feel free to comment. Thanks in advance!

Answer 1

Alright, sorry for the bad question format. Anyways, here is the solution to my question: the solution is fairly simple, all what happened is that I added an unneeded extra for loop for index in lists which unnessecarily added extra items to my list. the solution is as follows

row_1 = []
row_2 = []
row_3 = []
for lists in inputs:
    row_1.append(lists[0])
    row_2.append(lists[1])
    row_3.append(lists[2])

and if we continue with the example input above inputs = [[1,0,1], [1,1,1]] We do indeed get our desired output [1, 1] [0, 1] [1, 1]

to anyone who landed on this same question, just try and add a debugger under your tool belt, would be really useful. If not viable, don't get discouraged from the error, take a break and you will most likely figure it out.