执行本机插入查询后获取实体 ID + Spring JPA

Question

I am using a Native query in my JPA Repository to run INSERT query - because, I couldn't run a few queries through JPA.

String INSERT_USER_IN_TO_DATABASE = "INSERT INTO USER_MASTER " +
            "(" +
            "MOBILE_X,USER_TYPE,COUNTRYCODE,USER_N,USER_LAST_N,GENDER,DOB) " +
            "VALUES ( " +
            "EncryptByKey(Key_GUID(convert(varchar,?1)), ?2)," +
            "1,+91,?3,?4,?5,?6" +
            ")";

    @Query(value = INSERT_USER_IN_TO_DATABASE, nativeQuery = true)
    @Modifying
    UserMasterEntity saveNewUser(String encryptionKey,
                                 String phoneNumber,
                                 String name,
                                 String lastName,
                                 String gender,
                                 String dob);

My intention is to execute the INSERT statement and get me the userMaster entity. But I get the below exception

Caused by: java.lang.IllegalArgumentException: Modifying queries can only use void or int/Integer as return type! Offending method: public abstract com.officeride.fileprocess.job.bulkuser.UserMasterEntity com.officeride.fileprocess.job.bulkuser.UserMasterRepository.saveNewUser(java.lang.String,java.lang.String,java.lang.String,java.lang.String,java.lang.String,java.lang.String)

I used @ColumnTransformer stuff too in my entity and nothing is working out for me.

How to tackle this?

Answer 1

You cannot make the INSERT INTO statement return anything. Depending on your database's support, on that end you could execute multiple statements, eg, INSERT INTO...; SELECT... INSERT INTO...; SELECT... , but Spring Data JDBC does not support this.

• What you can do is implement saveNewUser and perform the insert then select, sequentially and synchronously. See this: https://docs.spring.io/spring-data/jdbc/docs/current/reference/html/#repositories.single-repository-behavior .
• If your database supports it, you could create a stored procedure that performs the insert then select.