检查数组中的所有用户是否至少有一个 ID 等于 ID 数组的元素？

Question

The title is very hard to read, I get it.

I have an array of objects with my users inside of it.

const users = [{
  id: 0,
  name: "Test user 01",
}, {
  id: 1,
  name: "Test user 02"
}, {
  id: 3,
  name: "Test user 03"
}]

const idsToCheck = [2, 4]; 

I want a boolean True if at least one element of users have an ID equal to 2 OR to 4.

I wanted to use Array.some but, with an array to check and not a single value, I cannot loop inside of the method without a lint error.

Thanks

Answer 1

Some does work.

We are testing numeric IDs against an array of ints - there is reference equality between the IDs and the array elements so the includes is the shortest method over a double some

 const users = [{ id: 0, name: "Test user 01", }, { id: 1, name: "Test user 02" }, { id: 3, name: "Test user 03" }] const idsToCheck = [2, 4]; const bool = users.some(({id}) => idsToCheck.includes(id)) console.log(bool)

Answer 2

Does this looks OK to you?

 const users = [{ id: 0, name: "Test user 01", }, { id: 1, name: "Test user 02" }, { id: 3, name: "Test user 03" }] const idsToCheck = [2, 4]; const isPresent = users.some(user => idsToCheck.some(id => id === user.id)); console.log(isPresent)