[英]How do I remove texts in brackets only from the beginning of lines with regex in Python?
I would like to remove all the line codes in brackets placed at the beginning of lines but want to preserve the other words in brackets.我想删除放在行首的括号中的所有行代码,但想保留括号中的其他单词。
\([^()]*\)
finds every text in brackets. \([^()]*\)
查找括号中的每个文本。
^\h*\([^()]*\)
finds only the first one but not the rest. ^\h*\([^()]*\)
只查找第一个,但不查找 rest。 How should I modify it?我应该如何修改它?
The sample text is the following:示例文本如下:
(#p0340r#) This is a sentence. This is another one but I need more sentences to fill the space to start a new line.
(#p0350q#) Why? (this text should be left unchanged)
(#p0360r#) Because I need to remove these codes from interview texts.
The expected outcome should be:预期结果应该是:
This is a sentence. This is another one but I need more sentences
to fill the space to start a new line.
Why? (this text should be left unchanged)
Because I need to remove these codes from interview texts.
Thank you!谢谢!
To remove a pattern at the start of any line with Python re.sub
, you need to use the ^
before the pattern (that is what you already have) and pass the re.M
flag using flags=re.M
or inline (in-pattern) (?m)
flag.要使用 Python re.sub
删除任何行开头的模式,您需要在模式之前使用^
(这是您已经拥有的)并使用flags=re.M
或 inline 传递re.M
标志(在-pattern) (?m)
标志。
Also, \h
is not Python re
compliant, you need to use a construct like [ \t]
or [^\S\n]
(in some rare cases, also [^\S\r\n]
, usually when you read a file in binary mode) to match any horizontal whitespace.此外, \h
不符合 Python re
兼容,您需要使用[ \t]
或[^\S\n]
之类的构造(在极少数情况下,也[^\S\r\n]
,通常当您阅读二进制模式的文件)以匹配任何水平空格。
So, you can use所以,你可以使用
re.sub(r'^[^\S\n]*\([^()]*\)[^\S\n]*', '', text, flags=re.M)
Note: if you ever want to remove one or more substrings inside parentheses at the start of a line group the pattern and apply the +
quantifier on it:注意:如果您想在行的开头删除一个或多个括号内的子字符串,请将该模式分组并在其上应用+
量词:
re.sub(r'^(?:[^\S\n]*\([^()]*\))+[^\S\n]*', '', text, flags=re.M)
# ^^^ ^^
See the Python demo :请参阅Python 演示:
import re
text = """(#p0340r#) This is a sentence. This is another one but I need more sentences to fill the space to start a new line.
(#p0350q#) Why? (this text should be left unchanged)
(#p0360r#) Because I need to remove these codes from interview texts."""
print( re.sub(r'^[^\S\n]*\([^()]*\)[^\S\n]*', '', text, flags=re.M) )
Output: Output:
This is a sentence. This is another one but I need more sentences to fill the space to start a new line.
Why? (this text should be left unchanged)
Because I need to remove these codes from interview texts.
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