[英]How to stop fold expression function calls in the middle when a condition is met and return that value?
I have functions foo
, bar
, baz
defined as follows:我有函数
foo
, bar
, baz
定义如下:
template <typename ...T>
int foo(T... t)
{
return (bar(t), ...);
}
template <typename T>
int bar(T t)
{
// do something and return an int
}
bool baz(int i)
{
// do something and return a bool
}
I want my function foo
to stop folding when baz(bar(t)) == true
and return the value of bar(t)
when that happens.我希望我的 function
foo
在baz(bar(t)) == true
时停止折叠,并在发生这种情况时返回bar(t)
的值。 How can I modify the above code to be able to do that?我怎样才能修改上面的代码才能做到这一点?
Use short circuit operator &&
(or operator ||
):使用短路
operator &&
(或operator ||
):
template <typename ...Ts>
int foo(Ts... t)
{
int res = 0;
((res = bar(t), !baz(res)) && ...);
// ((res = bar(t), baz(res)) || ...);
return res;
}
Note:笔记:
(baz(res = bar(t)) ||...);
would even be shorter, but less clear IMO.甚至会更短,但不太清楚 IMO。
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