[英]Difficult boo syntactic macro
I'm creating a DSL for an extensible card game engine I'm working on, with boo. 我正在使用boo为正在使用的可扩展纸牌游戏引擎创建DSL。
I have a card macro that creates a class for a new type of card, and initializes some properties in the constructor. 我有一个card宏,它为一种新型的card创建一个类,并在构造函数中初始化一些属性。 That macro has a few submacros for setting other things. 该宏具有一些用于设置其他内容的子宏。 Basically I want it to turn something like this: 基本上我希望它变成这样的东西:
card 'A new card':
type TypeA
ability EffectA:
// effect definition
into this: 到这个:
class ANewCard (Card):
def constructor():
Name = "A new card"
Type = Types.TypeA
AddEffect(EffectA())
class EffectA (Effect):
// effectdefintion
The effect definitely needs to be a class, because it will be passed around (it's a Strategy pattern). 效果肯定需要是一个类,因为它会被传递(这是一种策略模式)。
So far, I have this simple skeleton: 到目前为止,我有这个简单的框架:
macro card:
yield [|
class $(ReferenceExpression(card.Arguments[0])) (Card):
def constructor():
Name = $(card.Arguments[0])
|]
Now, I don't know what should I do with card.Body to make the ability macro add code to the constructor while also generating a nested class. 现在,我不知道该如何使用card.Body来使能力宏将代码添加到构造函数中,同时还要生成一个嵌套类。 Any thoughts? 有什么想法吗? Can this be done with current language capabilities? 可以使用当前的语言功能吗?
It can be done. 可以办到。 Here's how: 这是如何做:
import Boo.Lang.Compiler.Ast
import Boo.Lang.PatternMatching
macro card(name as string):
klass = [|
class $(ReferenceExpression(name)):
def constructor():
Name = $name
|]
klass.Members.Add(card["effect"])
klass.GetConstructor(0).Body.Add(card["effect-ctor"] as Expression)
yield klass
macro effect(eff as ReferenceExpression):
card["effect"] = [|
class $eff (Effect):
pass
|]
card["effect-ctor"] = [| Effects.Add($(eff)()) |]
Credit goes to Cedric Vivier for helping me out in the boo Google group . 感谢Cedric Vivier协助我加入Google boo小组 。
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