2个地方的列表的格式化元素问题

Question

I'm trying to format my data on 2 places. If it contains only 1 element, it should append 0 to it. For example new_time = [10,52] My desire output is [10,52 ] For [10,5] My desire output is [10,05] I read about this method new_time = [new_time[0],new_time[1]:02] . But output of this is invalid syntax. Does anybody know why it isn't work? I did similar exercise and it works.

Answer 1

It is not possible for integers to be denoted with leading zeroes, and it is by design. Try to run this statement into your python console: print(05) . You would get an error stating that

SyntaxError: leading zeros in decimal integer literals are not permitted; 
use an 0o prefix for octal integers

But you can typecast integers into strings and logically put leading zeroes if you need.

Answer 2

Integers(and Floats) can not be written with leading zeros. What you can do in this case is to convert them to string like this:

new_time = [10,5]
ls= [f'{_:02}' for _ in new_time]
print(ls) # Returns ['10', '05']

Answer 3

I'm afraid you can not display left-zeros for values of type int , unless you change them into str :

new_time = ["%02d"%i for i in new_time]

for which, new_time outputs:

['10', '05']

Answer 4

  new_time = [10, 5]
  formated_time = []
  for item in new_time:
  if item < 10:
     time = f"0{item}"
     formated_time.append(time)
  if item >= 10:
     time = item
     formated_time.append(time)
  print(formated_time)
  """note:but while using it again you should use type('int') before the item"""