如何对数组的前半部分按升序排序，后半部分按降序排序

Question

I currently have a Merge Sort algorithm up using Java but I am struggling with modifying it to sort the second half in descending order. It should also have a time complexity of O(n).

For example:

Input: 34, 12, 7, 43, 55, 97, 41, 28, 2, 62

Output: 2, 7, 12, 28, 34, 97, 62, 55, 43, 41

Answer 1

In java 1.8+ we can do it like this. we can optimize it further. :)

public static void main(String[] args) {
    Stream<Integer> streamObj = Stream.of(34, 12, 7, 43, 55, 97, 41, 28, 2, 62);
    List<Integer> list1 = streamObj.collect(Collectors.toList());
    int middleIndex = list1.size()/2;
    System.out.println(middleIndex);
    List<Integer> firstHalf = list1.subList(0,middleIndex).stream().sorted().collect(Collectors.toList());
    List<Integer> secondHalf = list1.subList(middleIndex,list1.size()).stream().sorted(Comparator.reverseOrder()).collect(Collectors.toList());
    System.out.println("firstHalf"+firstHalf+"\nsecondHalf"+secondHalf);
    firstHalf.addAll(secondHalf);
    System.out.println(firstHalf);
}