celery 在工作模式下启动时的运行代码

Question

I am looking to run some code when a celery worker starts. Not when let's say a task is imported to be used from a client type application.

celery_app = Celery(__name__)
# I want to only create the egine if this file is used by a worker
engine = create_engine(str(POSTGRES_URL))

Answer 1

You are looking for worker signals ( https://docs.celeryproject.org/en/latest/userguide/signals.html?highlight=worker_ready#worker-signals ). It is all nicely explained there. I am guessing worker_ready is the one you should look at first.