[英]how can i avoid no reverse match in django
I don't know why this error occurred no revers match
while I'm practicing Django.我不知道为什么在练习 Django 时出现此错误
occurred no revers match
。
I modified the shops.html code to link pizza but after this modifying, this error occurred我修改了shops.html代码来链接披萨,但是修改后,出现了这个错误
Reverse for 'pizza' with arguments '('',)' not found.
未找到 arguments '('',)' 的 'pizza' 反向。 1 pattern(s) tried: ['shops/(?P<pizza_id>[0-9]+)$']
尝试了 1 种模式:['shops/(?P<pizza_id>[0-9]+)$']
first code:第一个代码:
<ul>
{%for shop in shops%}
<li>
{{shop}}
</li>
second code:第二个代码:
<ul>
{%for shop in shops%}
<li>
<a href="{% url 'pizzas:pizza' pizza.id %}">{{shop}}</a></li>
I have Posted all codes in Pastebin if needed.如果需要,我已经在Pastebin中发布了所有代码。
your problem is that instead of shop.pk
you used pizza.id
and that is not actually defined.您的问题是您使用的是
pizza.id
shop.pk
实际上并未定义。
change this改变这个
{%for shop in shops%}
<li>
<a href="{% url 'pizzas:pizza' pizza.id %}">{{shop}}</a></li>
{%empty%}
<li>currently there is no pizza available</li>
{%endfor%}
to至
{%for shop in shops%}
<li>
<a href="{% url 'pizzas:pizza' shop.pk %}">{{shop}}</a></li>
{%empty%}
<li>currently there is no pizza available</li>
{%endfor%}
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