如何将元组和整数列表转换为嵌套字典？

Question

I have a list containing tuples and integers
eg

mylist = [ (('ART', 'bar'), 2), (('ART', 'get'), 1), (('b', 'bet'), 1), (('b', 'chest'), 1), (('b', 'kart'), 2), (('b', 'zee'), 1)]

which I want to convert to this nested dictionary

my_dict = {
    "ART": {"bar": 2, "get": 1},
    "b": {"bet": 1, "chest": 1, "kart": 2,"zee": 1}
}

I've been trying to do this using for loops but I'm a beginner and I don't have any experience with nested dictionaries so I really don't know where to start. I've looked at other questions related to dictionaries of dictionaries eg this and this but the methods suggested aren't working for me (I assume because I am dealing with tuples rather than just lists of lists.)

Answer 1

You could loop over the input and use setdefault to populate the dictionary:

my_dict = {}
for (key, prop), value in mylist:
    my_dict.setdefault(key, {})[prop] = value

Answer 2

Try this:

mylist = [ (('ART', 'bar'), 2), (('ART', 'get'), 1), (('b', 'bet'), 1), 

(('b', 'chest'), 1), (('b', 'kart'), 2), (('b', 'zee'), 1)]
mydict = dict()

for i in mylist:
    if i[0][0] not in mydict.keys():
        mydict[i[0][0]] = {i[0][1]: i[1]}
    else:
        mydict[i[0][0]][i[0][1]] = i[1]
print(mydict)

Answer 3

You can use collections.defaultdict :

from collections import defaultdict
my_dict = defaultdict(dict)
for (k1,k2),v in mylist:
    my_dict[k1][k2] = v
my_dict = dict(my_dict)

Output:

{'ART': {'bar': 2, 'get': 1}, 'b': {'bet': 1, 'chest': 1, 'kart': 2, 'zee': 1}}