[英]Python: read CSV row by row and create a file per row
Basically I want to read my CSV and create one text file per row.基本上我想阅读我的 CSV 并每行创建一个文本文件。
My CSV content is: Grenouille,1139,287,252,164,2017-03-04-21_35_19.jpg,1920,1080
我的CSV内容为: Grenouille,1139,287,252,164,2017-03-04-21_35_19.jpg,1920,1080
I've done the following code:我已经完成了以下代码:
import sys
import csv
with open('labels_grenouilles.csv', newline='') as csvfile:
spamreader = list(csv.reader(csvfile, delimiter=' ', quotechar='|'))
for row in spamreader:
f = open(str(spamreader[5]) + ".txt", "a")
f.write(str(spamreader[0]) + " " + str(spamreader[1]) + " " + str(spamreader[2]) + " " + str(spamreader[3]) + " " + str(spamreader[4]))
f.close()
but instead of creating each time a new file it creates something like that:但不是每次都创建一个新文件,而是创建类似的东西:
What am I missing?我错过了什么?
I see you're using the for
loop for each element of spamreader
.我看到您正在对spamreader
的每个元素使用for
循环。 In this case, your spamreader
is a list, so if you use spamreader[5]
to create a file you'll get the same value everytime, since you're using the 6th element of the list everytime in open()
.在这种情况下,您的spamreader
是一个列表,因此如果您使用spamreader[5]
创建一个文件,您每次都会得到相同的值,因为您每次都在open()
中使用列表的第 6 个元素。
Also using append
in (open(spamreader[5], "a")
this will create the file if it doesn't exist or will simply add at the end of its content if it exists.同样在(open(spamreader[5], "a")
中使用append
) 如果文件不存在,则将创建该文件,如果存在,则将其简单地添加到其内容的末尾。
So, in conclusion, you're opening the same file everytime because you're using spamreader[5]
in the for
loop, and that's the same value everytime.因此,总而言之,您每次都打开同一个文件,因为您在for
循环中使用spamreader[5]
,并且每次都是相同的值。
My guess is that you want to use row
in open()
instead of spamreader
我的猜测是你想在open()
中使用row
而不是spamreader
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