如果没有三个数字，如何格式化整数以便在它之前打印空格

Question

I want to print some sequence of number in a specific format. Like if there are 3 digits it will print the integer but if there are not 3 digits for example if there are two digits or one digit then it will make up spaces. For example:
__3 bench
_55 pencils
675 pens
I wanted to how can I format this. the numbers are always integers.

 for key, value in dict.items():
        print(f'{key:} {value}')

Answer 1

something like this by giving width to your paramater to print:

for key, value in dict.items():
    print (f'{key:>3} {value}')

output:

width = 3
for key, value in dict.items():
    print (f'{key:>{width}} {value}')

you can replace 3 with the maximum number of digits you might have in your data or even pass it dynamically:

 width = 3 for key, value in dict.items(): print (f'{key:>{width}} {value}')

Answer 2

You might use .rjust method after converting int to str . Consider following example

benches = 3
pencils = 55
pens = 675
print(str(benches).rjust(3),"benches")
print(str(pencils).rjust(3),"pencils")
print(str(pens).rjust(3),"pens")

output

  3 benches
 55 pencils
675 pens

Similar methods exists named .ljust (justing to left) and .center