删除字符出现直到第一个不同的字符，Java

Question

So I have some numerical strings like the following ones:所以我有一些数字字符串，如下所示：

"00000545468" - "00002021" - "000000001990" etc.. (I don't know how this strings will be passed to me, the only thing I know is that they will start with some zeros from left and then there will be other different numbers) “00000545468”-“00002021”-“000000001990”等。（我不知道这些字符串将如何传递给我，我唯一知道的是它们将从左边的一些零开始，然后会有其他不同的数字）

I want to remove all the zeros (0) occurrences from left until the first different number of the string.我想从左边删除所有出现的零 (0) 直到字符串的第一个不同数字。 So if I have for example "00002021", I want to have as a result "2021" and if I have "000000001990" I want "1990".因此，如果我有例如“00002021”，我希望结果是“2021”，如果我有“000000001990”，我想要“1990”。

I excluded the usage of .replace("0", "") , because by doing this I would also remove the zero in "2021" and in "1990", and I don't want this to happen.我排除了.replace("0", "")的使用，因为这样做我也会删除“2021”和“1990”中的零，我不希望这种情况发生。

Any suggestions?有什么建议么？

Answer 1

You can use the replaceFirst method of String which takes a regex as its first argument to archieve that.您可以使用 String 的replaceFirst方法，该方法将正则表达式作为其第一个参数来存档。

eg:例如：

System.out.println("00002021".replaceFirst("0+", ""));

will print将打印

删除字符出现直到第一个不同的字符，Java

问题描述

1 个解决方案

解决方案1
0 2021-12-06 16:37:10

删除字符出现直到第一个不同的字符，Java

问题描述

1 个解决方案

解决方案1 0 2021-12-06 16:37:10

解决方案1
0 2021-12-06 16:37:10