[英]How can I run a DateTime with for or foreach loop to loop through each day and add +3 days to each?
I have 2 dates in PHP, how can I run a for or foreach loop to loop through each day and add +3 days to each?我在 PHP 中有 2 个日期,我如何运行一个 for 或 foreach 循环来循环每一天并添加 +3 天?
below I add an example of how I want to get the listing.下面我添加了一个如何获取列表的示例。
<?php
$begin = new DateTime( "2022-01-01" );
$end = new DateTime( "2022-01-31" );
for($i=$begin; $i<=$end; $i->modify('+1 day')){
for($j=$begin; $j<=$end; $j->modify('+3 day')){
echo $i->format("M d, Y").' => ';
echo $j->format("M d, Y").'<br/><br/>';
/* I WANTS TO GET
* Jan 01, 2022 => Jan 04, 2022
* Jan 02, 2022 => Jan 05, 2022
* Jan 03, 2022 => Jan 06, 2022
*...
*...
* Jan 31, 2022 => Feb 03, 2022
*/
}
}
?>
Using the DateInterval()
and DatePeriod()
its a simple case of setting the parameters and running a loop使用
DateInterval()
和DatePeriod()
是设置参数和运行循环的简单案例
$begin = new DateTime( "2022-01-01" );
$end = new DateTime( "2022-01-31" );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $dateFrom){
$to = clone $dateFrom;
echo sprintf("%s => %s\n",
$dateFrom->format("M d, Y"),
$to->modify('3 day')->format("M d, Y")
);
}
RESULT结果
Jan 01, 2022 => Jan 04, 2022
Jan 02, 2022 => Jan 05, 2022
Jan 03, 2022 => Jan 06, 2022
Jan 04, 2022 => Jan 07, 2022
Jan 05, 2022 => Jan 08, 2022
Jan 06, 2022 => Jan 09, 2022
Jan 07, 2022 => Jan 10, 2022
Jan 08, 2022 => Jan 11, 2022
Jan 09, 2022 => Jan 12, 2022
Jan 10, 2022 => Jan 13, 2022
Jan 11, 2022 => Jan 14, 2022
Jan 12, 2022 => Jan 15, 2022
Jan 13, 2022 => Jan 16, 2022
Jan 14, 2022 => Jan 17, 2022
Jan 15, 2022 => Jan 18, 2022
Jan 16, 2022 => Jan 19, 2022
Jan 17, 2022 => Jan 20, 2022
Jan 18, 2022 => Jan 21, 2022
Jan 19, 2022 => Jan 22, 2022
Jan 20, 2022 => Jan 23, 2022
Jan 21, 2022 => Jan 24, 2022
Jan 22, 2022 => Jan 25, 2022
Jan 23, 2022 => Jan 26, 2022
Jan 24, 2022 => Jan 27, 2022
Jan 25, 2022 => Jan 28, 2022
Jan 26, 2022 => Jan 29, 2022
Jan 27, 2022 => Jan 30, 2022
Jan 28, 2022 => Jan 31, 2022
Jan 29, 2022 => Feb 01, 2022
Jan 30, 2022 => Feb 02, 2022
If the end date is always simply three days from the start, then you only need one loop, over the start date.如果结束日期总是距开始日期仅三天,那么您只需要一个循环,超过开始日期。 Then, instead of a second loop to set the ending date, just set it relative to the start, on each iteration:
然后,不是第二个循环来设置结束日期,而是在每次迭代时将其设置为相对于开始日期:
for ($start = $begin; $start <= $end; $start->modify('+1 day')) {
$stop = clone $start;
$stop->modify('+3 days');
printf("%s => %s\n", $start->format("M d, Y"), $stop->format("M d, Y"));
}
Note you need to make a new date object via clone so that your second modification of +3 days
doesn't change the start date.请注意,您需要通过克隆创建一个新日期 object,以便您的第二次修改
+3 days
不会更改开始日期。
You can also just use the same DateTime object for all of it if you like.如果您愿意,您也可以只使用相同的 DateTime object。
for ($i = $begin; $i <= $end; $i->modify('-2 day')) {
echo $i->format("M d, Y") . ' => ';
echo $i->modify('+3 day')->format("M d, Y") . '<br><br>';
}
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