如何将嵌套列表中的值更改为字典中指定的值？

Question

I have this code in which I have a list of lists and inside the sub-lists we got numbers. However, I also have a dict storing key-value pairs of name-number, in which the number is the index of the name stored in another list, but I want to replace all the numbers in the nested list with their respective names. Instead of having [1,9,13] I want to have ['The Beach Chimney', 'Parlay', 'The Private Exhibit'].

out = [(ind,ind2) for ind,i in enumerate(rows) 
                  for ind2,y in enumerate(i) if y == '1']

list_of_restaurants_index = []
for empty_list in range(100):
  empty_list = []
  list_of_restaurants_index.append(empty_list)

for i in out:
  for empty_list in list_of_restaurants_index:
    if i[0] == list_of_restaurants_index.index(empty_list):
      empty_list.append(i[1])
print(list_of_restaurants_index)

restaurants_dict = {}
for i in header:
  restaurants_dict[i] = header.index(i)

Output:

[[1, 9, 13], [8, 14, 17], [6, 14], [4, 8, 9, 12], [1, 2, 5, 6, 12, 13, 18], [1, 4, 5, 8, 10, 11, 12], [1, 12, 14, 16], [3, 4, 5, 13, 14, 17, 18], [4, 9, 10, 12, 13, 14, 15, 18], [3, 16], [1, 3, 5, 10, 13], [1, 5, 10, 15, 17], [2, 4, 6, 7, 10, 13], [2, 4, 9, 12], [9, 11, 12, 13], [1, 3, 4, 7, 9, 17], [6, 8, 9, 10, 11, 13, 14, 15, 18], [2, 4, 6, 7, 8, 13], [4, 7, 10, 11, 13, 14, 16, 18], [7, 12, 16, 17, 18], [3, 7, 10, 13, 14], [1, 2, 3, 5, 8, 12, 14, 17, 18], [8, 10, 12, 13, 16, 17], [4, 5, 6, 7, 8, 11, 17], [1, 4, 7, 9, 13, 16], [4, 10, 12, 14, 15], [2, 3, 4, 11, 13, 14, 15, 17], [1, 2, 7, 8, 9, 16], [5, 6, 7], [4, 5, 6], [10, 16, 18], [6, 13, 14, 17], [1, 6, 16, 17], [1, 2, 4, 5, 10, 12, 15, 18], [3, 4, 10, 12, 14, 16, 18], [1, 2, 6, 8, 9, 11, 13, 14, 16, 17], [5, 6, 7], [1, 2, 5, 10, 13, 18], [4, 5, 13, 18], [5, 7, 9, 10, 11, 12, 15, 17], [2, 14], [4, 5, 9, 11, 12, 14], [1, 3, 5, 10, 11, 15], [3, 12, 13, 16], [1, 4, 5, 6, 7, 9, 11, 13, 14, 15], [4, 6, 9, 13, 15, 16, 18], [2, 3, 4, 6, 9, 12, 14, 15], [1, 7, 12, 14, 17], [5, 6, 8, 10, 11, 12, 15, 18], [2], [2], [4, 5, 7, 11, 12, 14], [1, 4, 9, 14, 18], [3, 6, 8, 15, 18], [1, 4, 7, 8, 14], [3, 4, 7, 11, 15], [1, 4, 5, 6, 10, 13, 14, 15, 16, 18], [2], [2], [5, 6, 8, 14, 15, 16, 18], [6], [8, 10, 12, 16], [1, 4, 5, 10, 14, 17, 18], [6], [5, 6, 9, 10, 13, 14], [1, 11, 12, 17], [1, 5, 10, 14, 15], [3, 4, 6, 9, 10, 15, 18], [4, 8, 10, 16, 17, 18], [4, 7, 14, 17], [1, 2, 3, 9, 16], [10, 12, 14, 16], [1, 2, 8, 10, 15], [1, 2, 4, 10, 13, 17], [3, 7, 17], [4, 5, 6], [4, 6, 11, 12, 17], [1, 2, 7, 8, 13, 16], [1, 2, 4, 8, 13], [8, 11], [1, 4, 5, 6, 7, 18], [1, 4, 5, 11, 12, 14, 17], [5, 8, 9, 14], [2], [4, 5, 7, 10, 14, 16], [6], [1, 2, 3, 4, 7, 11, 13, 14], [7, 12, 14], [3, 4, 7, 11, 13], [1, 2, 3, 4, 6, 7, 8, 9, 14, 15], [2], [6], [5, 12, 15, 16, 17, 18], [3, 4, 5, 11, 12, 13], [3, 5, 6, 14, 17, 18], [9, 12, 13, 15], [4, 14, 15, 16, 18], [4, 8], [3], [3]]

Also, here's what the dict is storing:

{'': 0, 'The Beach Chimney': 1, "The Pirate's Harvest": 2, 'The Square Dragon': 3, 'The Spicy Trumpet': 4, 'Vertigo': 5, 'Drifters': 6, 'The Tulip': 7, 'Seawise': 8, 'Parlay': 9, 'The Modern Salmon': 10, 'The Bitter Windmill': 11, 'The Minty Window': 12, 'The Private Exhibit': 13, 'Enigma': 14, 'The Lighthouse': 15, 'Harlequin': 16, 'Midnight': 17, 'Gastrognome': 18}

obs: header is a list containing the names.

Answer 1

Having trouble making out where you are starting from, but starting from your output of the list of integers and the dict at the end of your question, you could do this:

inverted_dict = {restaurants_dict[k]:k for k in restaurants_dict}

rest_names = []
for i in range(len(list_of_restaurants_index)):
    row = []
    for j in range(len(list_of_restaurants_index[i])):
        row.append(inverted_dict[list_of_restaurants_index[i][j]])
    rest_names.append(row)

"rest_names" should be what you want, I think.
This creates a new list, rather than editing the members of your original list. Not sure if that matters to you.

Answer 2

Not sure the purpose of the dict.

empty_list.append(i[1]) seems to be appending a number

That number happens to align with the indicies of the strings you want.

Therefore, you could instead use

name = header[i[1]]
empty_list.append(name)