如何从 Python 日期时间 object 中提取年份？

Question

I would like to extract the year from the current date using Python.

In C#, this looks like:

 DateTime a = DateTime.Now() 
 a.Year

What is required in Python?

Answer 1

It's in fact almost the same in Python.. :-)

import datetime
year = datetime.date.today().year

Of course, date doesn't have a time associated, so if you care about that too, you can do the same with a complete datetime object:

import datetime
year = datetime.datetime.today().year

(Obviously no different, but you can store datetime.datetime.today() in a variable before you grab the year, of course).

One key thing to note is that the time components can differ between 32-bit and 64-bit pythons in some python versions (2.5.x tree I think). So you will find things like hour/min/sec on some 64-bit platforms, while you get hour/minute/second on 32-bit.

Answer 2

import datetime
a = datetime.datetime.today().year

or even (as Lennart suggested )

a = datetime.datetime.now().year

or even

a = datetime.date.today().year

Answer 3

The other answers to this question seem to hit it spot on. Now how would you figure this out for yourself without stack overflow? Check out IPython , an interactive Python shell that has tab auto-complete.

> ipython
import Python 2.5 (r25:51908, Nov  6 2007, 16:54:01)
Type "copyright", "credits" or "license" for more information.

IPython 0.8.2.svn.r2750 -- An enhanced Interactive Python.
?         -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help      -> Python's own help system.
object?   -> Details about 'object'. ?object also works, ?? prints more.

In [1]: import datetime
In [2]: now=datetime.datetime.now()
In [3]: now.

press tab a few times and you'll be prompted with the members of the "now" object:

now.__add__           now.__gt__            now.__radd__          now.__sub__           now.fromordinal       now.microsecond       now.second            now.toordinal         now.weekday
now.__class__         now.__hash__          now.__reduce__        now.astimezone        now.fromtimestamp     now.min               now.strftime          now.tzinfo            now.year
now.__delattr__       now.__init__          now.__reduce_ex__     now.combine           now.hour              now.minute            now.strptime          now.tzname
now.__doc__           now.__le__            now.__repr__          now.ctime             now.isocalendar       now.month             now.time              now.utcfromtimestamp
now.__eq__            now.__lt__            now.__rsub__          now.date              now.isoformat         now.now               now.timetuple         now.utcnow
now.__ge__            now.__ne__            now.__setattr__       now.day               now.isoweekday        now.replace           now.timetz            now.utcoffset
now.__getattribute__  now.__new__           now.__str__           now.dst               now.max               now.resolution        now.today             now.utctimetuple

and you'll see that now.year is a member of the "now" object.

Answer 4

If you want the year from a (unknown) datetime-object:

tijd = datetime.datetime(9999, 12, 31, 23, 59, 59)

>>> tijd.timetuple()
time.struct_time(tm_year=9999, tm_mon=12, tm_mday=31, tm_hour=23, tm_min=59, tm_sec=59, tm_wday=4, tm_yday=365, tm_isdst=-1)
>>> tijd.timetuple().tm_year
9999

Answer 5

It's easy to extract the year as follows.

from datetime import datetime

year = datetime.today().year