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如何在 r 中创建相似度矩阵?

[英]How do I create similarity matrices in r?

I have a matrix with legislators on the rows, issues on the columns, and values indicating how legislators voted on a given issue (0 - absent, 1 - for, 2 - against).我有一个矩阵,行上是立法者,列上是问题,以及指示立法者如何对给定问题进行投票的值(0 - 缺席,1 - 支持,2 - 反对)。 I need to create a similarity matrix (whether or not two legislators voted the same way if they were both present for the vote) for each issue.我需要为每个问题创建一个相似性矩阵(如果两位立法者都出席投票,他们是否以相同的方式投票)。 Is there a quick way of doing that in r without using nested for loops?在 r 中有没有使用嵌套 for 循环的快速方法?

Here is how the matrix looks like:这是矩阵的样子:

    I1 I2 I3 I4
L1   1  1  1  2
L2   1  1  0  0
L3   2  2  2  2
L4   2  2  0  0

Here is what I would like to get for the first issue:这是我想为第一个问题得到的:

   L1 L2 L3 L4
L1     1  0  0
L2  1     0  0
L3  0  0     1
L4  0  0  1

You may try你可以试试

func <- function(a, b) {ifelse(a==b & a*b != 0, 1, 0)}

lapply(dummy, function(x) {
  res <-outer(x, x, func)
  diag(res) <- NA
  colnames(res) = rownames(res) = c("L1", "L2", "L3", "L4")
  res
  })


$I1
   L1 L2 L3 L4
L1 NA  1  0  0
L2  1 NA  0  0
L3  0  0 NA  1
L4  0  0  1 NA

$I2
   L1 L2 L3 L4
L1 NA  1  0  0
L2  1 NA  0  0
L3  0  0 NA  1
L4  0  0  1 NA

$I3
   L1 L2 L3 L4
L1 NA  0  0  0
L2  0 NA  0  0
L3  0  0 NA  0
L4  0  0  0 NA

$I4
   L1 L2 L3 L4
L1 NA  0  1  0
L2  0 NA  0  0
L3  1  0 NA  0
L4  0  0  0 NA

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