提取R中混合月份和年份字符串的总月数

Question

I have a dataframe that includes a column with values like:

"Sentenced to 2years and 90 years"
"Sentenced to 5years and 6months"
"Sentenced to 3months"

I need to only get the total number of months for each of them, how can I do this?

"Sentenced to 2years and 90 years" would give 1104 "Sentenced to 5years and 6months" would give 66 "Sentenced to 3months" would give 3

Answer 1

Does this give you the expected result?

library(stringr)
my_year <- str_extract_all(string = "Sentenced to 5years and 6month", pattern = "[0-9]+ ?years?", simplify = TRUE)
my_month <- str_extract_all(string = "Sentenced to 5years and 6month", pattern = "[0-9]+ ?months?", simplify = TRUE)


my_year <- sum(as.double(str_extract(string = my_year, pattern = "[0-9]+"))) * 12
my_month <- sum(as.double(str_extract(string = my_month, pattern = "[0-9]+")))

my_result <- my_year + my_month

One extract for the years and one for the month, then we just multiply the number of years per 12 since there are 12 months in a year and we add the months we extracted