Go 使用 \.. 在字符串路径中向上一个目录 - Python os.path

Question

I'm writing a post-job script for Thinkbox Deadline. I need the directory for the rendered frames from a finished Cinema 4D job.

In Cinema, we had the frames know to go up a few directories, then back down to a different location by using this syntax "path\to\c4d_file....\renders\frame_00.png"

In this example the ".." tells Cinema to go up 2 folders to the "path" folder then back down into the "renders" folder where it saves the renders to.

Unfortunately Deadline doesn't calculate the actual path when it makes the render job. When I tell the post-job script to go to the path location, it doesn't understand the '..' -- so I need to tell it where to go up a directory and where to go back down.

Is there any sort of Python magic that can basically read the ".." and know how to make the correct directory?

Thanks

Answer 1

Take the absolute path and remove the last one

path.sep.join(path.abspath('.').split(path.sep)[:-1])