Not exists 子句未按预期工作

Question

I want to search every company ( niu_lds ) that does NOT have any Analyst ( cod_role_acces ) working for it.

Example: Let's say there is a company X with 3 employees. One of them is an analyst. I would not want that company to come up in my results. but if there is company Y with 2 employees, and none of them is an "analyst", then I would like this company to come up in the result.

This is my query:

SELECT DISTINCT
    a.name_pers as "First Name",
    a.last_pers as "Last Name",
    a.id as "# account",
    a.cod_role_acces as "Profile", 
    a.niu_lds as "Company", 
    b.cod_missn as "Mission", 
    
FROM sr.c_r_v_obt_cp_util a inner join ods.c_od_missn_ld b on a.niu_lds = b.niu_lds

WHERE a.cod_eta_util in ('VER', 'APPR')
and a.id_cod_sr_alim = '2'
and b.cod_missn = 'PHA'

 and not exists (select null
                 from sr.c_r_v_obt_cp_util c 
                 where c.niu_lds = a.niu_lds
                 and a.cod_role_acces = 'ANALYST'
                );

My problem is it's returning me "company" that HAVE "analyst(s)". I want to see all the company (niu_lds) that has no 'ANALYST'(cod_role_access) attributed to said company.

I already asked the question, and someone helped me a lot but I'm still not getting the expected output.

my first question: SQL query to check if a value isn't present

Thank you

Answer 1

I believe the answer from Romeo with changing the null to 1 might get you there.

If it doesn't and you want to see visually what's happening to compare, you could turn the not exists function into a left join so you can see where values are getting placed.

Using the test example from the previous post -

with test (company, ename, profile) as
      (select 'BMW', 'Scott', 'Analyst' union all
       select 'BMW', 'King' , 'Manager' union all
      select 'BMW', 'Mike' , 'Clerk'  union all
      select 'SAP', 'John' , 'Clerk' union all
      select 'SAP', 'Fred' , 'Manager' 
    )
  select a.company, a.ename, a.profile, b.analyst
  from test a
  left join (select 1 as analyst, company
        from test
        where profile = 'Analyst') b
        using(company)

The following is the return -

COMPANY	ENAME	PROFILE	ANALYST
BMW	Scott	Analyst	1
BMW	King	Manager	1
BMW	Mike	Clerk	1
SAP	John	Clerk	null
SAP	Fred	Manager	null

You can see that all of BMW is getting marked for Analyst, from here, if you wanted to build off the left join rather than not exists but 'hide' the column marking Analyst, add 'where b.analyst is null' and remove b.analyst from the select statement -

with test (company, ename, profile) as
      (select 'BMW', 'Scott', 'Analyst' union all
       select 'BMW', 'King' , 'Manager' union all
      select 'BMW', 'Mike' , 'Clerk'  union all
      select 'SAP', 'John' , 'Clerk' union all
      select 'SAP', 'Fred' , 'Manager' 
    )
  select a.company, a.ename, a.profile
  from test a
  left join (select 1 as analyst, company
        from test
        where profile = 'Analyst') b
        using(company)
where b.analyst is null

This returns the expected table -

COMPANY	ENAME	PROFILE
SAP	John	Clerk
SAP	Fred	Manager

Answer 2

You can try the code below;

WITH all_roles AS (
SELECT *,
      SUM(CASE WHEN cod_role_acces = 'ANALYST' THEN 1 ELSE 0 END) OVER (PARTITION BY niu_lds ORDER BY niu_lds ) AS rolecount
FROM sr.c_r_v_obt_cp_util
)
SELECT DISTINCT
    a.name_pers as "First Name",
    a.last_pers as "Last Name",
    a.id as "# account",
    a.cod_role_acces as "Profile", 
    a.niu_lds as "Company", 
    b.cod_missn as "Mission"
FROM all_roles a inner join ods.c_od_missn_ld b on a.niu_lds = b.niu_lds
WHERE a.cod_eta_util in ('VER', 'APPR')
AND a.id_cod_sr_alim = '2' AND b.cod_missn = 'PHA'
AND a.rolecount < 1;