这个正则表达式在 Entrypoint.sh 中做了什么？

Question

Can someone tell me what this line means?

Entrypoint.sh:

export NAME="$(sed -e 's/^"//' -e 's/"$//' <<<"$NAME")"

All I know is that its performing regex to the variable $NAME but I dont know what exactly its doing. I've tried using RegExr.com but it tells me that the expression is wrong.

Answer 1

It removes any starting and ending quotes. It is using 2 regexes: s/^"// and s/"$// . First one substitutes a starting quote with nothing and the latter substitutes an ending quote with nothing.