[英]Getting the button name in PyQT5
I'm working on a simple tic-tac-toe game with gui using PyQt5.我正在使用 PyQt5 使用 gui 开发一个简单的井字游戏。 The interface is all set up but I'm having a bit of trouble with a function.
接口已全部设置,但我在使用 function 时遇到了一些问题。 The interface is a 3x3 grid of buttons.
该界面是一个 3x3 的按钮网格。 When you click one of these buttons, it dropsdown a choice of X or O. Whichever choice you click on, that becomes the text of the button.
当您单击其中一个按钮时,它会下拉选择 X 或 O。无论您单击哪个选项,它都会成为按钮的文本。
class App(QMainWindow):
game_board = {
'btn1': '', 'btn2': '', 'btn3': '',
'btn4': '', 'btn5': '', 'btn6': '',
'btn7': '', 'btn8': '', 'btn9': ''
}
def __init__(self):
super().__init__()
self.title = 'Tic-Tac-Toe'
self.top = 100
self.left = 100
self.width = 375
self.height = 375
self.initUI()
def initUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.top, self.left, self.width, self.height)
...___...
# buttons that make up the gameboard
self.btn1 = QPushButton(self.game_board['btn1'], self)
self.btn2 = QPushButton(self.game_board['btn2'], self)
self.btn3 = QPushButton(self.game_board['btn3'], self)
self.btn4 = QPushButton(self.game_board['btn4'], self)
self.btn5 = QPushButton(self.game_board['btn5'], self)
self.btn6 = QPushButton(self.game_board['btn6'], self)
self.btn7 = QPushButton(self.game_board['btn7'], self)
self.btn8 = QPushButton(self.game_board['btn8'], self)
self.btn9 = QPushButton(self.game_board['btn9'], self)
self.btns = {'btn1': self.btn1, 'btn2': self.btn2, 'btn3': self.btn3, 'btn4': self.btn4, 'btn5': self.btn5, 'btn6': self.btn6, 'btn7': self.btn7, 'btn8': self.btn8, 'btn9': self.btn9}
x_o_menu = QMenu(self)
x_o_menu.addAction('X', self.x_action)
x_o_menu.addAction('O', self.o_action)
i = 1
for value in self.btns.values():
if i < 4:
value.setGeometry(75*i, 75, 75, 75)
elif i < 7:
value.setGeometry(75*(i-3), 150, 75, 75)
elif i < 10:
value.setGeometry(75*(i-6), 225, 75, 75)
i += 1
value.setMenu(x_o_menu)
self.show()
...___...
def x_action(self):
sender = self.sender()
self.statusBar().showMessage(sender.text() + ' was pressed')
def o_action(self):
pass
The closest solution I've found so far has been to use self.sender() but that doesn't return the button, rather it returns the dropdown option (which as I'm typing this I realize I could probably use to turn x_action and o_action into a single method), but I still have no way of knowing which button to update the text for.到目前为止我发现的最接近的解决方案是使用 self.sender() 但这不会返回按钮,而是返回下拉选项(当我输入这个时,我意识到我可能会用它来打开 x_action和 o_action 合并为一个方法),但我仍然无法知道要为哪个按钮更新文本。 Is there a way to do this without giving a unique menu to each button?
有没有办法在不为每个按钮提供唯一菜单的情况下做到这一点?
A QMenu, just like a QAction, can be shown/used by any parent. QMenu,就像 QAction 一样,可以被任何父母展示/使用。 It can also be shown without any actual parent.
它也可以在没有任何实际父级的情况下显示。 So your approach is actually invalid.
所以你的方法实际上是无效的。
Since your board will clearly have a limited range of buttons, adding a unique menu to each button won't create that big overhead, so a possibility is to create individual menus for each button.由于您的电路板显然具有有限范围的按钮,因此为每个按钮添加一个独特的菜单不会产生那么大的开销,因此可以为每个按钮创建单独的菜单。
A better approach, though, would be to create a subclass of QPushButton and add a unique QMenu for that button.不过,更好的方法是创建 QPushButton 的子类并为该按钮添加一个唯一的 QMenu。 Then you need to create a custom signal for the button class, and you can connect that signal from the main program using the custom signature or, eventually, a lambda.
然后您需要为按钮 class 创建一个自定义信号,您可以使用自定义签名或最终使用 lambda 从主程序连接该信号。
Please note that creating direct child widgets for a QMainWindow is discouraged, as well as using fixed geometries;请注意,不鼓励为 QMainWindow 创建直接子窗口小部件以及使用固定几何图形; as the documentation suggests :
正如文档所示:
Note: Creating a main window without a central widget is not supported.
注意:不支持创建没有中央小部件的主 window。 You must have a central widget even if it is just a placeholder.
即使它只是一个占位符,您也必须有一个中央小部件。
You should properly create a central widget (a basic QWidget would suffice), then use setCentralWidget()
and set up a layout manager for that central widget.您应该正确地创建一个中央小部件(一个基本的 QWidget 就足够了),然后使用
setCentralWidget()
并为该中央小部件设置一个布局管理器。 Then , you can add the buttons to that layout.然后,您可以将按钮添加到该布局。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.