从 csv 列中分离日期和时间

Question

I have a CSV file which has a column datetime in this format:

|datetime   | dataA |dataB|
---------------------------
|211201000000 | 1 | 222
|211201000000 | 11|221
|211201000000 | 12|111
|211201000000 | 11|144
|211201000000 | 13|1122

I want to write datetime column in this format(format='%Y-%m-%d %H:%M:%S'):

2021-12-01 00:00:00
2021-12-01 00:00:00
2021-12-01 00:00:00
2021-12-01 00:00:00
2021-12-01 00:00:00

I am using this line to change my datetime column:

df['datetime'] = pd.to_datetime(df['datetime'], format='%Y-%m-%d %H:%M:%S')

or

df['datetime'] = pd.to_datetime(df['datetime']).dt.date

Output I get in datetime column from above lines are:

1970-01-01 }
.........
........

which are not even in CSV columns.

But these lines don't change my date time as I expect.

How can I change them in to my desire format so that I can use it easily in further work?

Answer 1

The format you need to use is %y%m%d%H%M%S . A short example:

from datetime import datetime as dt

s = "211201000000"

dt.strptime(s, "%y%m%d%H%M%S")

OUTPUT

datetime.datetime(2021, 12, 1, 0, 0)