随后的 MongoDB aggregate() 调用对上一次调用的结果进行操作？？ （使用 NodeJS 驱动程序）

Question

Consider the following code:

const db = mongodb.getDb();
            
// Results count
let count = (await db.collection('sec').aggregate(aggregateQuery)
    .group({ _id: null, count: { $sum: 1 } })
    .project({ _id: 0, count: 1 })
    .toArray());
console.dir(count)

// test
let test = await db.collection('sec').aggregate(aggregateQuery).toArray();
console.dir(test)

The aggregate(aggregateQuery) filters the collection ad performs a lookup with another collection. The first query counts all documents resulting from the aggregate, and it outputs [ { count: 2086 } ] as expected.
In my mind, test should contain a bunch of documents filtered from the collection (according to the aggregate operations), but it is just [ { count: 2086 } ] , as in the first query!

If in the second query instead of aggregate(aggregateQuery) I put find() , it outputs all the collection's documents, as expected, so I guess there is something I am missing in the aggregate() function...

Answer 1

The object passed as a parameter inside aggregate ( aggregateQuery in this case) is modified by the following functions ( group and project ), so when it is used again in the second aggregate call, it is different and yields different results.