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如何从具有不同类型的可变参数模板初始化 std::vector?

[英]How to initialize a std::vector from variadic templates with different type each?

My main problem is that i'm trying to create a function that initialize a std::vector of a class that can be initialized by different ways, so I decided to use variadic templates, but, like in this example, that does not compile:我的主要问题是我正在尝试创建一个 function 来初始化可以通过不同方式初始化的 class 的std::vector ,所以我决定使用可变参数模板,但是,就像在这个例子中一样,它不会编译:

#include <iostream>
#include <string>
#include <vector>

using namespace std;

struct MyClass {
    MyClass(int v): value(v){}
    MyClass(string v): value(stoi(v)){}
    int value;
};

template<typename ...Args> vector<MyClass> mc_vector(const Args &...args);

int main()
{
    auto vec = mc_vector(1, "3", 5);
    for (auto &i : vec)
        cout << i.value << " ";
    cout << endl;
}

template<typename ...Args, typename T> void mc_vector_(vector<MyClass>& vec, const Args &...args, const T& t) {
    vec.emplace_back(t);
    mc_vector_(vec, args...);
}

template<typename ...Args> vector<MyClass> mc_vector(const Args &...args) {
    vector<MyClass> vec;
    vec.reserve(sizeof...(args));
    mc_vector_(vec, args...);
    return vec;
}

And actually, i would like to know if you image a smarter way of doing this.实际上,我想知道您是否想像一种更聪明的方式来做到这一点。

You need to put the variadic argument last and you could use a fold-expression to populate vec .您需要将可变参数放在最后,您可以使用折叠表达式来填充vec You could also make it do perfect forwarding :你也可以让它做完美的转发

#include <utility> // std::forward

template<typename... Args, typename T> 
void mc_vector_(vector<MyClass>& vec, T&& t, Args&&... args) {
    vec.emplace_back(std::forward<T>(t));
    (mc_vector_(vec, std::forward<Args>(args)), ...); // fold-expression
}

template<typename ...Args>
vector<MyClass> mc_vector(Args&&... args) {
    vector<MyClass> vec;
    vec.reserve(sizeof...(args));
    mc_vector_(vec, std::forward<Args>(args)...);
    return vec;
}

The top function could be simplified to:顶部的 function 可以简化为:

template<typename... Args> 
void mc_vector_(vector<MyClass>& vec, Args&&... args) {
    (vec.emplace_back(std::forward<Args>(args)), ...); // fold-expression
}

If you really want a recursive call:如果你真的想要一个递归调用:

template<typename... Args, typename T> 
void mc_vector_(vector<MyClass>& vec, T&& t, Args&&... args) {
    vec.emplace_back(std::forward<T>(t));    
    if constexpr (sizeof...(Args) > 0) mc_vector_(vec, std::forward<Args>(args)...);
}

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