[英]Javascript JSON array of objects to HTML table
I am new to javascript.我是 javascript 的新手。 I also tried different solutions in the forums.
我还在论坛中尝试了不同的解决方案。 I want to print object data into a html table (tr>td).
我想将 object 数据打印到 html 表中(tr>td)。 I need to pull this data from a url.
我需要从 url 中提取这些数据。 The JSON structure is as given in the example.
JSON 结构如示例中所示。 Also, the output of the data needs to be side by side.
另外,数据的output需要并排。 I tried with the code block below but it didn't work.I tried the suggested answers in this forum.
我尝试了下面的代码块,但没有成功。我在这个论坛上尝试了建议的答案。 All the data is coming, but what I want is to list the information of one person side by side on each line.
所有的数据都来了,但我想要的是在每一行并排列出一个人的信息。 How can I solve this?
我该如何解决这个问题? Thank you.
谢谢你。
Note: 1-I know the answer in this link (It is not duplicate quesion).注意:1-我知道此链接中的答案(这不是重复的问题)。 But as I said I want to sort the data side by side.
但正如我所说,我想并排对数据进行排序。 2-I am not creating this data.
2-我没有创建这些数据。 I need to get it from a url like this.
我需要像这样从 url 那里得到它。
{ "name": [ "John", "Marie", "Clara" ], "surname": [ "Doe", "Jane", "Smith" ], "phone": [ "1233215555", "1233215555", "1233215555" ], "birthdate": [ "1980-12-14", "1990-02-13", "1995-03-10" ] } fetch(url).then(res => res.json()).then((out) => { for (let i = 0; i < out.length; i++) { console.log(out[i][name] + " " + out[i][surname] + " " + out[i][phone] + " " + out[i][birthdate]) } })
The order is wrong.顺序是错误的。 out is an object of arrays (not an array of objects).
out 是 arrays 的 object (不是对象数组)。 Here I fixed the order of access with the assumption, that all properties contain an array with the same length:
在这里,我通过假设所有属性都包含一个长度相同的数组来固定访问顺序:
function fetch() { return Promise.resolve({ json() { return Promise.resolve({ "name": [ "John", "Marie", "Clara" ], "surname": [ "Doe", "Jane", "Smith" ], "phone": [ "1233215555", "1233215555", "1233215555" ], "birthdate": [ "1980-12-14", "1990-02-13", "1995-03-10" ] }) } }); } var url = "some-url"; fetch(url).then(res => res.json()).then((out) => { for (let i = 0; i < out.name.length; i++) { console.log(out.name[i] + " " + out.surname[i] + " " + out.phone[i] + " " + out.birthdate[i]) } })
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