从 python 中多行的字符串中提取

Question

I have been trying to extract the particular substring from multiple lines in Python.

The string goes for 400 lines...with foreign characters as well(for instance Chinese)

The example is my_string = '''\n1. Up in the air: 悬而未决\n2. Out of the woods: 摆脱困境\n3. Not all there: 智商掉线\n''' my_string = '''\n1. Up in the air: 悬而未决\n2. Out of the woods: 摆脱困境\n3. Not all there: 智商掉线\n''' my_string = '''\n1. Up in the air: 悬而未决\n2. Out of the woods: 摆脱困境\n3. Not all there: 智商掉线\n''' all the way to 400. Born to the purple: 出身显赫.

What I want to do: Extract only the English part and put them in a list

[Up in the air, Out of the woods, Not all there]

Here is my way of doing it.

import re
my_list = re.split('\:.*\n',my_string[1:])

for line in my_list[-1]:
olist = re.sub('\d.','',line)
print (olist) 

Is that possible to do this in one line?

Thank you

Answer 1

" ".join(re.findall(r'[a-zA-Z]+', my_string))

> 'Up in the air Out of the woods Not all there'

Answer 2

If you wanted 3 elements in your list (or 400 with your full input):

re.findall(r"\d\. (.*):", my_string)

Gives:

['Up in the air', 'Out of the woods', 'Not all there']

Answer 3

if you want the English word in a list you can do something like this:

import re
line='''\n1. Up in the air: 悬而未决\n2. Out of the woods: 摆脱困境\n3. Not all there: 智商掉线\n'''
line = re.sub(r"[^A-Za-z\s]", "", line.strip())
words = line.split()
eng_list=[]
for word in words:
    eng_list.append(word)
print(eng_list)

OUTPUT:

['Up', 'in', 'the', 'air', 'Out', 'of', 'the', 'woods', 'Not', 'all', 'there']

Else if you want the eng word in a single string and in list than you can go for this:

import re
line='''\n1. Up in the air: 悬而未决\n2. Out of the woods: 摆脱困境\n3. Not all there: 智商掉线\n'''
line = re.sub(r"[^A-Za-z\s]", "", line.strip())
words = line.split()
eng_list=[]
letter=''
for word in words:
    letter+=word+' '
    # eng_list.append(word)
eng_list.append(letter.strip())
print(eng_list)

OUTPUT

['Up in the air Out of the woods Not all there']