如何从第一个和第二个 position 手动从 Kotlin ZE84E30B9390CDB4864DZDB6C

Question

See this LinkedHashMap

var sizeMap: LinkedHashMap<String, ProductSize>? = null

So, from API this sizemap value I'm storing, but not sure how to retrieve it. I checked and map size is coming 2.

Without for loop, I manually want to get sizeMap[0] and sizeMap[1] and want to store in ProductSize object. But not able to do it.

I tried below, but compiler error is coming in [0]

val sizeObj = it[0]

Answer 1

A LinkedHashMap is not a list, it is still a map. What you could do is

sizeMap.values()[0]

Answer 2

First of all, sizeMap in your example is nullable. You can't do anything with it before you make sure it is not null.

Secondly, LinkedHashMap keeps ordering of elements, but that doesn't mean it allows to access its Nth element. We still need to iterate over it to get an element at a specific index.

Fortunately, Kotlin provides many utils to make it possible to iterate without actual iterating in the source code. For example, we can take first two values from the map like this:

if (sizeMap != null) {
    val (first, second) = sizeMap.values.take(2)
}