[英]How do I convert an any array to a string array containing other datatypes inside in typescript?
I'm doing a typescript tutorial exercise that wants me to change an any[] array into string[].我正在做一个 typescript 教程练习,希望我将任何 [] 数组更改为字符串 []。
// declaring an array of any datatype
const manufacturers: any[] = [{ id: 'Samsung', checked: false },
{ id: 'Motorola', checked: false },
{ id: 'Apple', checked: false },
{ id: 'Sony', checked: false }
];
console.log('Available Products are: ');
// logic to populate the above declared array's id value
for (const item of manufacturers) {
console.log(item.id);
if(item.id === "Apple")
{
console.log("check value is " + item.checked)
}
}
The above one works, but if I change any[] into string[], it doesn't work.上面的一个有效,但是如果我将任何[]更改为字符串[],它就不起作用。 If I do
如果我做
"const manufacturers: [string,boolean][]="
then it recognizes the boolean and not the string. "const manufacturers: [string,boolean][]="
然后它识别 boolean 而不是字符串。 I'm trying to understand why it doesn't see id as a string variable and make it match.我试图理解为什么它不将 id 视为字符串变量并使其匹配。 How do I accomplish this without using 'any[]'
如何在不使用“任何 []”的情况下完成此操作
The type of manufacturers
is { id: string, checked: boolean }[]
. manufacturers
的类型是{ id: string, checked: boolean }[]
。
Explanation:解释:
The manufacturers
object is an array, containing objects. manufacturers
object 是一个数组,包含对象。 Each object has an id
and a checked
property which are of types string and boolean respectively.每个 object 都有一个
id
和一个checked
属性,它们分别是 string 和 boolean 类型。
So as you said, changing from any[]
to string[]
won't work, because the manufacturers
type is not string[]
, but { id: string, checked: boolean }[]
.正如您所说,从
any[]
更改为string[]
将不起作用,因为manufacturers
类型不是string[]
,而是{ id: string, checked: boolean }[]
。
const manufacturers: { id: string, checked: boolean }[] = [{ id: 'Samsung', checked: false },
{ id: 'Motorola', checked: false },
{ id: 'Apple', checked: false },
{ id: 'Sony', checked: false }
];
console.log('Available Products are: ');
for (const item of manufacturers) {
console.log(item.id);
if (item.id === "Apple") {
console.log("check value is " + item.checked)
}
}
As @Calz pointed out, you don't need to explicitly enter the type of the variable, as initialization is taking place at the time of declaration.正如@Calz 指出的那样,您不需要显式输入变量的类型,因为初始化是在声明时进行的。
Here's a small example explaining this:这是一个解释这一点的小例子:
let a;
a = 5
console.log(typeof a) // number
a = "string"
console.log(typeof a) // string
let b = 5
b = "some string"; // error as TypeScript blames that type string is not assignable to type number
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