Groovy map（带有项目的数组position）到对象的Z466DEEC76ECDF5FCA6D38571F6324D54

Question

Input:

import groovy.json.JsonBuilder
new JsonBuilder([test: 'test', test2: 'test2']).toPrettyString()

or

import groovy.json.JsonOutput
JsonOutput.prettyPrint(JsonOutput.toJson([test: 'test', test2: 'test2']))

Output:

{
   "test" : "test",
   "test2" : "test2"
}

But how I will process the following in groovy language?

Input:

[test : 'test', testing[0].T1_Id : 'test1', testing[1].T2_Id : 'test2']

Output:

{
   "test" : "test",
   "testing" : [
      {
         "T1_Id" : "test1"
      },
      {
         "T2_Id" : "test2"
      }
   ]
}

Answer 1

def data = [
   "test" : "test",
   "testing" : [
      [
         "T1_Id" : "test1"
      ],
      [
         "T2_Id" : "test2"
      ]
   ]
]
new JsonBuilder(data).toPrettyString()

should return you the desired json