[英]How to convert char to int in array (JavaScript)
How to change char value in array to int value?如何将数组中的char值更改为int值? and detect first element and second element in array
并检测数组中的第一个元素和第二个元素
arr = [a,a,a,b,b,a,b]
first element = a第一个元素 = a
second element = b第二个元素 = b
a = 1, b = 2
My expected output我的预期 output
arr = [1,1,1,2,2,1,2]
Something like this should work (I used NodeJs console):像这样的东西应该可以工作(我使用了 NodeJs 控制台):
> let a = ['a','a','a','b','b','a','b']
undefined
> a
[
'a', 'a', 'a',
'b', 'b', 'a',
'b'
]
> var result = []
> for (var i = 0; i < a.length; i++){
... result.push(a[i].charCodeAt(0))
... }
7
> result
[
97, 97, 97, 98,
98, 97, 98
]
You can do it like so.你可以这样做。
You can only get the char code of an index in a string.您只能获取字符串中索引的字符代码。 Since we have an char array we can alsways get the index of
0
.由于我们有一个 char 数组,我们总是可以得到
0
的索引。 The smallest charcode is of A
which is 65. In this example I transform a
to A
which resolves to 65
then I remove 64 since a
should be 1
.最小的字符代码是
A
,它是 65。在这个例子中,我将a
转换为A
,它解析为65
然后我删除 64 因为a
应该是1
。 Consecutively b
is mapped to B
which is 65 and resolves to 2
since 64 is removed连续
b
映射到B
是 65 并解析为2
因为 64 被删除
const arr = ['a','a','a','b','b','a','b'] const res = arr.map(char => char.toUpperCase().charCodeAt(0) - 64) console.log(res)
do this arr.map((x)=>{ return x.toString()})这样做 arr.map((x)=>{ return x.toString()})
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