如何将表格中的数据插入到表格中

Question

I have a form which I want to be auto-completed with data from a table I made. How can I achieve this? This is my table:

    while($row  = mysqli_fetch_assoc($result))
    {
        echo "<tr>";
        echo "<td>" . $row['ID_Angajati'] . "</td>";
        echo "<td>" . $row['Nume'] . "</td>";
        echo "<td>" . $row['Prenume'] . "</td>";
        echo "<td>" . $row['CNP'] . "</td>";
        echo "<td>" . $row['Data_Nasterii'] . "</td>";
        echo "<td>" . $row['Sex'] . "</td>";
        echo "<td>" . $row['Numar_Telefon'] . "</td>";
        echo "<td>" . $row['Salariu'] . "</td>";
        echo "<td class = container_update ><button type = 'button' onclick = 'yes_js_modal();'>Update</a></td>";
        echo "<td class = container_delete ><a href = 'includes/delete.php?id=$row[ID_Angajati]'>&times;</a></td>";
        echo "</tr>";
    }
    echo "</table>";

And this is my form:

<form action="" method="POST">
<table align="center">

<tr>
<td>ID_Angajati:</td>
<td><input type = "text" name="ids" required></td>
</tr>

<tr>
<td>Nume:</td>
<td><input type = "text" name="nume" required></td>
</tr>

<tr>
<td>Prenume:</td>
<td><input type = "text" name="prenume" required></td>
</tr>

<tr>
<td>CNP:</td>
<td><input type = "text" name="cnp" required></td>
</tr>

<tr>
<td>Data Nasterii:</td>
<td><input type = "text" name="data" required></td>
</tr>

<tr>
<td>Sex:</td>
<td><input type = "text" name="sex" required></td>
</tr>

<tr>
<td>Numar Telefon:</td>
<td><input type = "text" name="nr_telf" required></td>
</tr>

<tr>
<td>Salariu:</td>
<td><input type = "text" name="sal" required></td>
</tr>

<tr>
<td colspan = "2" align = "center">
<input type="submit" id="button" name="submit" value="Update Details"></a>
</td>
</tr>

</table>
</form>

I want for instance ID_Angajati from my form to be auto-completed in the form with the value of one of my rows in the table. This will happen when I click on the "Update" button from the table.

Answer 1

If you want to do it without sending the form you'll need Javascript. But if you want to do it with PHP, you can do it on the same file. By the way you did it, it will print all the data that you have on the database, but here is the code:

<?php 
    function appear_form()
    {
        while($row = mysqli_fetch_assoc($result))
        {
            echo "<table align='center'>";
            echo "<tr>";
            echo "<td>ID_Angajati:</td>";
            echo "<td>{$row['ID_Angajati']}</td>";
            echo "</tr>";
            echo "<td>Nume:</td>";
            echo "<td>{$row['Nume']}</td>";
            echo "</tr>";
            echo "<td>Prenume:</td>";
            echo "<td>{$row['Prenume']}</td>";
            echo "</tr>";
            echo "<tr>";
            echo "<td>CNP:</td>"
            echo "<td>{$row['CNP']}</td>";
            echo "</tr>";
            echo "<tr>";
            echo "<td>Data Nasterii:</td>";
            echo "<td>{$row['Data_Nasterii']}</td>";
            echo "</tr>";
            echo "<tr>";
            echo "<td>Sex:</td>";
            echo "<td>{$row['Sex']}</td>";
            echo "</tr>";
            echo "<tr>";
            echo "<td>Numar Telefon:</td>";
            echo "<td>{$row['Numar_Telefon']}</td>";
            echo "</tr>";
            echo "<tr>";
            echo "<td>Salariu:</td>";;
            echo "<td>{$row['Salariu']}</td>";
            echo "</tr>";
            echo "</table>";
        }
      
    }

    if(isset($_POST['submit']))
    {
        
        appear_form();
    }
    
?>
<form action="" method="post">
    <button type="submit" id="submit" name="submit">Update Details</button>
</form> 

PHP interact with the server so it could only manage GET, POST, etc requests. If you want something more elaborated you'll need to use Javascript.