[英]How to regex match list of patterns in python
I have list of patterns and I need to return that pattern if that is present in the given string else return None.我有模式列表,如果给定字符串中存在该模式,我需要返回该模式,否则返回无。 I tried with the below code using re module, but I am getting only null in "matches" (when I tried to print matches).
我尝试使用 re 模块使用以下代码,但我在“匹配”中只得到 null(当我尝试打印匹配时)。 Completely new to corepython and regex,kindly help
对 corepython 和 regex 完全陌生,请帮助
import re
patterns_lst=['10_TEST_Comments','10_TEST_Posts','10_TEST_Likes']
def get_matching pattern(filename):
for pattern in patterns_lst:
matches = re.(pattern,filename)
if matches:
return matches
else:
return None
print(get_matching pattern("6179504_10_TEST_Comments_22-Nov-2021_22-Nov-2021.xlsx"))
I have made some changes to your function:我对您的 function 做了一些更改:
def get_matching_pattern(filename): ## Function name changed
for pattern in patterns_lst:
match = re.search(pattern, filename) ## Use re.search method
if match: ## Correct the indentation of if condition
return match ## You also don't need an else statement
Output: Output:
>>> print(get_matching_pattern("6179504_10_TEST_Comments_22-Nov-2021_22-Nov-2021.xlsx"))
<re.Match object; span=(8, 24), match='10_TEST_Comments'>
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