如何使用 spring 引导从数据库 MYSQL 数据库创建动态菜单

Question

I have been trying to load the menu from database using spring jpa and spring boot with Mysql database.

But I have to load only active menu from database I have tried with JPQL ie findByActiveTrue() menthod of JPA but getting all records.

@Entity
@Table(name = "menu_tbl")
//@Cacheable
//@org.hibernate.annotations.Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)

public class Menu implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column(name = "menu_description")
    private String menuName;

    @Column(name = "menu_link", nullable = false)
    private String link;

    @Column(name = "menu_css")
    private String css;

    @Column(name = "menu_ico")
    private String icon;
     
    @Column(name = "active")
    @
    private Boolean active;

    @JsonManagedReference
    @OneToMany(mappedBy = "parent")
    @OrderBy("id ASC")
    private Set<Menu> children;

    @ManyToOne
    @JsonBackReference
    private Menu parent;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getMenuName() {
        return menuName;
    }

    public void setMenuName(String menuName) {
        this.menuName = menuName;
    }

    public String getLink() {
        return link;
    }

    public void setLink(String link) {
        this.link = link;
    }

    public String getCss() {
        return css;
    }

    public void setCss(String css) {
        this.css = css;
    }

    public String getIcon() {
        return icon;
    }

    public void setIcon(String icon) {
        this.icon = icon;
    }

    public Set<Menu> getChildren() {
        return children;
    }

    public void setChildren(Set<Menu> children) {
        this.children = children;
    }

    public Menu getParent() {
        return parent;
    }

    public void setParent(Menu parent) {
        this.parent = parent;
    }

    public Boolean getActive() {
        return active;
    }

    public void setActive(Boolean active) {
        this.active = active;
    }

}

Repository

public interface MenuRepository extends JpaRepository<Menu, Long> {
    
    
    List<Menu> findByActiveTrue();

}

And getting output

[ { "id": 1, "menuName": "Customer", "link": "/customer", "css": null, "icon": null, "active": true, "children": [ { "id": 2, "menuName": "Add Customer", "link": "/addCustomer", "css": null, "icon": null, "active": false, "children": [] }, { "id": 3, "menuName": "View Customer", "link": "/viewCustomer", "css": null, "icon": null, "active": false, "children": [] } ] } ]

Could Any one suggests? Thanks in Advance

enter image description here

Answer 1

I would do like this:

@Entity
@Table(name = "menu_tbl")
public class Menu {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column(name = "menu_description")
    private String menuName;

    @Column(name = "menu_link", nullable = false)
    private String link;

    @Column(name = "menu_css")
    private String css;

    @Column(name = "menu_ico")
    private String icon;

    @Column(name = "active")
    private Boolean active;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "main_id",
            nullable = true)
    private Menu mainMenu;

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "mainMenu", cascade = CascadeType.REMOVE)
    private Set<Menu> children = new HashSet<>();
}

And

List<Menu> findAllByMainMenuIdAndActiveIsTrue(Long mainMenuid);